Difference between revisions of "Talk:Extending Scripts (Papyrus)"
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imported>Qazaaq (→Using constant scripts and inheritance overrides: new section) |
imported>Qazaaq |
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| Line 10: | Line 10: | ||
EndFunction | EndFunction | ||
</source> | </source> | ||
<source lang="papyrus"> | |||
ObjectReference[] LinkedRefs = SomeObject.GetLinkedRefChildren() | |||
int i = 0 | |||
while(i < LinkedRefs.Length) | |||
LinkedRefs[i].Disable() | |||
i +=1 | |||
endwhile | |||
</source> | |||
For example, let's say you have the example above, your Disable function will not be called unless you explicitly cast the object as that type in a call to disable. | For example, let's say you have the example above, your Disable function will not be called unless you explicitly cast the object as that type in a call to disable. | ||
If instead you remove Const, when the native Disable function is called, it will use your override version as expected. [[User:Scrivener07|Scrivener07]] ([[User talk:Scrivener07|talk]]) 2018-07-05T01:06:38 (EDT) | If instead you remove Const, when the native Disable function is called, it will use your override version as expected. If a DisableCheck object was among those, the overridden version of Disable() will be called. As long as DisableCheck is not a Const type. [[User:Scrivener07|Scrivener07]] ([[User talk:Scrivener07|talk]]) 2018-07-05T01:06:38 (EDT) | ||
Revision as of 01:10, 5 July 2018
Using constant scripts and inheritance overrides
If you extend a script, and your extended script is of type Const. Any functions you override are ignored.
Scriptname DisableCheck extends ObjectReference Const
Function Disable(Bool abFade = false)
; Do Cleanup here
Parent.Disable(abFade)
EndFunctionObjectReference[] LinkedRefs = SomeObject.GetLinkedRefChildren()
int i = 0
while(i < LinkedRefs.Length)
LinkedRefs[i].Disable()
i +=1
endwhile
For example, let's say you have the example above, your Disable function will not be called unless you explicitly cast the object as that type in a call to disable.
If instead you remove Const, when the native Disable function is called, it will use your override version as expected. If a DisableCheck object was among those, the overridden version of Disable() will be called. As long as DisableCheck is not a Const type. Scrivener07 (talk) 2018-07-05T01:06:38 (EDT)